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Anon25 [30]
3 years ago
11

2(x + 2) + 3x = 2(x + 1) + 1

Mathematics
1 answer:
monitta3 years ago
4 0

Answer:

X= -1/3

Step-by-step explanation:

In the picture it shows the work that i did

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X less than 42 is 15<br><br> Which equation represents this scenario?
Lelu [443]

Answer:

42 is 15

Step-by-step explanation:

42 is 15 because of x

4 0
3 years ago
A survey was conducted that asked 1004 people how many books they had read in the past year. Results indicated that x overbarequ
melisa1 [442]

Answer:

Step-by-step explanation:

Given that a survey was conducted that asked 1004 people how many books they had read in the past year.

Results are:

x bar =12.5

s = 16.6

n = 1004

Std error of sample = \frac{s}{\sqrt{n-1} } =\frac{16.6}{\sqrt{1003} }\\=0.524152\\=0.524

Since population std dev is not known t critical value can be used for confidence interval.

df = 1004-1 =1003

t critical = 1.96

Margin of error = 1.96(std error) =1.027

Confidence interval lower bound = 12.5-1.027 = 11.473

Upper bound = 12.5+1.027 = 13.527

6 0
3 years ago
I NEED HELP PLSSS<br><br> Find the value of x.
tankabanditka [31]

Answer:

1) x= 43

2) x= 54

Step-by-step explanation:

you add the two angles given, then take that answer and subtract it from 180!

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7 0
3 years ago
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Which is greater between 222³³³ or 333²²²
iogann1982 [59]
222 ..........................................
6 0
4 years ago
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A political candidate has asked you to conduct a poll to determine what percentage of people support him. If the candidate only
Nadusha1986 [10]

Answer:

The sample size required is, <em>n</em> = 502.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p\cdot (1-\hat p)}{n}}

The margin of error is:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

Assume that 50% of the people would support this political candidate.

The margin of error is, MOE = 0.05.

The critical value of <em>z</em> for 97.5% confidence level is:

<em>z</em> = 2.24

Compute the sample size as follows:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

       n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}

           =[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502

Thus, the sample size required is, <em>n</em> = 502.

4 0
3 years ago
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