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Ronch [10]
3 years ago
13

Leigh has a piece of rope that is 6 2/3 feet long. How do you write 6 2/3 as a fraction greater than 1

Mathematics
2 answers:
aleksley [76]3 years ago
4 0
20/3 - Take the 6 2/3, multiply the 6 and the 3 (6 x 3 = 18), then add the 2 (18 + 2 = 20). Put that number over the original 3 and you've got yourself a mixed number.
weqwewe [10]3 years ago
4 0

Answer:

 \frac{20}{3} an improper fraction greater than 1.            

Step-by-step explanation:

 Given : Leigh has a piece of rope that is  6\frac{2}{3} feet long.

To write :  6\frac{2}{3} as a fraction greater than 1.

Solution :

Step 1 - Write the expression

6\frac{2}{3} it is in the mixed fraction form

Step 2 - Convert mixed fraction into fraction follow the steps:

Step (a) - Multiply the denominator by the whole number   3\times6 = 18

Step (b) - Add the answer from Step (a) to the numerator   18+2=20

Step (c) - Write answer from Step (b) over the denominator    \frac{20}{3}

Therefore, the required fraction is   \frac{20}{3}

We know in a fraction if numerator is greater than the denominator, the fraction is called an improper fraction and an improper fraction is always greater than 1.

Numerator 20>3 denominator

Hence, The required fraction is greater than 1.


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Bingel [31]

Answer:

4 balloon would expect to be orange

3 0
3 years ago
Two walls have the same area. The first wall is in the shape of a square and has a height
STatiana [176]

Answer:

27 feet

Step-by-step explanation:

Two walls have same area

Area of first wall(square) = 18*18 = 324

Area of second wall = 12 * x = 324

324/12 = 27

27 feet

7 0
3 years ago
NEED HELP I need to fill in the highlighted parts
Gemiola [76]

The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

Prove \ x = \dfrac{62}{9}

Statement                   {} Reason

S1. 9·(x + 6) - 41 = 75   {}  R1. <u>Given</u>

S2. 9·(x + 6)  =  116        {}R2. <u>Addition property</u>

S3. <u>9·x + 54 = 116 </u>         {}R3. Distributive property

S4. 9·x = 62                   {}R4. <u>Subtraction property</u>

S5. x = \dfrac{62}{9}                     {} R5. <u>Division property of equality</u>

Question 2.

Statement                                     {}        Reason

S1. m∠A + m∠B = m∠D   {}                     R1.  Given

S2. ∠C and ∠D form a Linear Pair   {}   R2. Definition of linear pair

S3. ∠C and ∠D are supplementary   {}R3. <u>Linear pair ∠s are supplementary</u>

S4. <u>∠C + ∠D = 180° </u>  {}                           R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180°   {}         R5. <u>Substitution property</u>

Question 3.

Statement                                     {} Reason

S1. ∠BDA ≅ ∠A                             {} R1. Given

S2. ∠BDA ≅ ∠CDE                      {}  R2. <u>Vertical angle theorem</u>

S3. ∠CDE ≅ ∠A                      {}       R3. Transitive property of congruency

S4. m∠CDE = m∠A                    {}   R4. <u>Definition of congruency</u>

S5. <u>(13·x + 20)° = (14·x + 15)°</u>      {}   R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5°                       {}R6. <u>Subtraction property</u>

S7. x = 5                      {}                  R7. Subtraction property

Learn more here:

brainly.com/question/11331230

6 0
3 years ago
3 3/4 x 4<br><br> Help me pas
alexandr1967 [171]
Convert any mixed numbers to fractions.
Then your initial equation becomes:

15
4
×
4
1
Applying the fractions formula for multiplication,

=
15
×
4
4
×
1

=
60
4
Simplifying 60/4, the answer is
15
4 0
2 years ago
Read 2 more answers
A basketball player shoots a basketball that reaches a height above 15 feet before landing back on the ground exactly after 7 se
Papessa [141]

Answer:

I and IV

Step-by-step explanation:

Since the height of the basketball reaches above 15 feet, hence the maximum of the function should be greater than 15 feet. Also at 7 seconds, the ball is on the ground, hence f(7) = 0 feet

The maximum of a function is at x = -b/2a

i) f(x) = -(x-3)² + 16 = -(x² - 6x + 9) + 16 = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 16 = 16 > 15

Also f(7) = - (7 - 3)² + 16 = 0

Hence this option is correct

ii) f(x) = -x² + 8x - 7

The maximum of a function is at x = -b/2a = -8 / 2(-1) = 4

f(4) = -4² + 8(4) - 7 = 9 < 15   not correct

Also f(7) = - 7² + 8(7) - 7 = 0

Hence this option is not correct since the maximum f(4) = 9 < 15  

iii)  f(x) = -(x-3)² + 14 = -(x² - 6x + 9) + 14 = -x² + 6x + 5

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 14 = 14 < 15

Also f(7) = - (7 - 3)² + 14 = -2

Hence this option is not correct since the maximum f(4) = 9 < 15 and f(7) ≠ 0

iv)f(x)  = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3)² + 6(3) + 7 = 16 > 15

Also f(7) = - (7)² + 6(7) + 7 = 0

Hence this option is correct

3 0
3 years ago
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