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Tom [10]
3 years ago
8

Graph a line that contains the point (-7,-4)and has a slope of - 2/3

Mathematics
1 answer:
sergeinik [125]3 years ago
7 0

Hi there! :)

Answer:

Given the information, we can write an equation in slope-intercept form

(y = mx + b) to graph the line:

Plug in the slope for 'm', the y-coordinate of the point given for 'y', and the

x-coordinate given for 'x':

-4 = -2/3(-7) + b

-4 = 14/3 + b

Solve for b:

-12/3 = 14/3 + b

-12/3 - 14/3 = b

-26/3 = b

Therefore, the equation of the line is y = -2/3x - 26/3 (Graphed below)

Some points on the line include:

(-7, -4)

(-4, -6)

(0, -26/3)

(2, -10)

(5, -12)

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Solve your system of equations step by step.

x−2y=14;x+3y=9

Solve x−2y=14 for x:

x−2y+2y=14+2y (Add 2y to both sides)

x=2y+14

Substitute (2y+14) for x in x+3y=9:

x+3y=9

2y+14+3y=9

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Answer:

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Step-by-step explanation:

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