<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
The formula for the area of a circle is A = (pi)r^2
So if you plugged in the numbers you would get this equation A = (3.14)97^2
Solve the equation and you would get your answer which is 29544.26
Hope this helps! :)
Answer:
1
2
6
Step-by-step explanation:
1/2 +1/2 =1
length 1/2 ×4=2
wide 1/2 ×3 =1 1/2
height 1/2×3= 1 1/2
