This is done by reducing each number by a common factor for each formula.
C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)
H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)
C8H8S2- all can be divided by 2 -> C4H4S
P5O15- all can be divided by 5- PO3
*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****
Answer:
MgSO4. 7H2O
There are seven water molecules attached to the hydrated salt.
Explanation:
From the equation;
Number of moles of hydrated salt = number of moles of anhydrous salt, we obtain:
Mass of hydrated salt/ molar mass of hydrated salt = mass of anhydrous salt/ molar mass of anhydrous salt
From the question;
Mass of hydrated salt = 1.000g
Molar mass of hydrated salt = 120.366 +18x gmol-1
Mass of anhydrous salt= 0.488g
Molar mass of anhydrous salt= 120.366 gmol-1
Substituting into the equation above;
1.000/120.366 +18x = 0.488/120.366
1.000/120.366 +18x = 0.004
1.000= 0.004 (120.366 +18x)
1.000= 0.48 + 0.072x
1.000 - 0.48 = 0.072x
0.52= 0.072x
x= 0.52/0.072
x=7
Therefore the hydrated salt is MgSO4. 7H2O
Answer:
Again please specify your question, you still haven't indicated what you want to be solved.
by formula units I assume you mean atoms?
I'll edit my answer accordingly if you could specify down in the comments.
Answer : The balanced reduction half-reaction is:
Explanation :
Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.
Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.
Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.
The given balanced redox reaction is :
The half oxidation-reduction reactions are:
Oxidation reaction : 
Reduction reaction : 
In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.
Oxidation reaction : 
Reduction reaction :
The balanced redox reaction will be:
Thus, the balanced reduction half-reaction is:
