X^2+7x-8>0 eliminating denominator
Factoring (x+8)(x-1) must be positive so
Case 1 both positive is x>-8 and x>1. For both to occur x>1
Case 2 both are negative (x+8)<0 and (x-1)<0 so x<-8 and x<1. For both to occur x<-8
Therefore x<-8 or x>1
Hello,
What we want to do is multiply 1/6 by each value within the parentheses individually.
So, it would be:
(1/6) * (18x) = 3x
(1/6) * (-24) = -4
Together, this would be 3x-4.
Hope this helps!
Answer:
2\sqrt(10)
Step-by-step explanation:
2, 10 squared
<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>
<em><u>-XxDeathshotxX</u></em>
F(x)=(4x-3)^-1(10))
(-4x+3(10))
(-4x(30))
i think that's how you would solve it i can't quite remember if you substitute the x with the 10 but if you do it would be
f(x)=4(10)-3
40-3
37
but im pretty sure it's the first way.
