Let’s find 1% of the markup first.
20 x 0.01 = $0.20
$0.20 x 8 = $1.60 markup.
$20 + $1.60 = $21.60 total.
Adrianna made $21.60 total, including markup.
Hope that helped! :)
X= y(d-b) over a-c would be the answer
18 cups, if you triple the amount without changing the percentage of strawberry, then the amount of strawberry yoghurt is also tripled
Answer:
Bottom left graph
Step-by-step explanation:
We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:
−2x + y ≤ 4 >> Original Standard Equation
+ 2x + 2x
_________
y ≤ 2x + 4 >> Slope-Intercept Equation
−2[0] + 0 ≤ 4
0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]
[We shade the part of the graph that does not contain the origin, which is the left side.]
So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.
** By the way, you meant 
because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.
I am joyous to assist you anytime.
Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
