A number divisible by 5 but not by 2 but the number should be even

Mathematics

1 answer:

Triss [41]3 years ago

8 0

Answer:

By definition an even number is evenly divisible by 2, so either your question is wrong or there is no answer. To be divisible by 5 the number must end in a 0 or a 5

Step-by-step explanation:

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the original cost of a piano is 19,100 and it is on a sale for 19% off its original price if the total l cost includes a 5% sale

amid [387]

Answer:

16,244.55

Step-by-step explanation:

Original cost of piano = 19,100

19% off on 19,100 = 0.19*19100 = 3,629

Selling cost = 19100 - 3629 = 15471

Sales tax = 5% =0.05

Amount of sales tax = 0.05*15471 = 773.55

Total selling cost of piano = Selling cost + Amount of sales tax = 15471 + 773.55 = 16,244.55

4 0

3 years ago

Read 2 more answers

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$