1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katena32 [7]
3 years ago
12

Rewrite the following numbers in their best form

Mathematics
1 answer:
timurjin [86]3 years ago
5 0
A. 70.105
b. 950
c. 0.0072
You might be interested in
What is the measure of angle A?
Zina [86]

Answer:

It b

Step-by-step explanation:

6 0
3 years ago
Draw a number line to represent the inequality.<br> 8&gt;x
Lilit [14]
Thts the answer because 8 is bigger than X the arrow goes to the left because 8 is bigger than numbers 1-7

6 0
3 years ago
Deangelo has $7 worth of dimes and quarters in a jar. He has 7 more quarters than dimes.
svlad2 [7]
D=number of dimes
q=number of quarters

let's count everything in cents
dimes are worth 10 cents
quarters are worth 25 cents

10d+25q=700
divide both sides by 5
2d+5q=140


he has 7 more quarters than dimes
q=7+d
subsitute 7+d for q in other equation

2d+5q=140
2d+5(7+d)=140
2d+35+5d=140
7d+35=140
minus 35 both sides
7d=105
divide both sides by 7
d=15

sub back

q=7+d
q=7+15
q=22


22 quarters and 15 dimes
3 0
3 years ago
Read 2 more answers
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
Make 'm' the subject of the formula'k=3m-2
zaharov [31]

Answer:

m =  \frac{k + 2}{3}

Step-by-step explanation:

k = 3m - 2 \\ 3m = k + 2 \\ m =  \frac{k + 2}{3}

4 0
3 years ago
Read 2 more answers
Other questions:
  • Alanina has 28$ in her account. she wants
    11·1 answer
  • Which of the following most accurately describes why trade-offs are necessary?
    10·1 answer
  • Two angle measures of a quadrilateral are 34° and 66°. What could the measure of the other two angles be?
    10·1 answer
  • Write two decimals that are equivalent to 5.300
    13·2 answers
  • Simplify 2(3x+7)-4(7+x)
    5·1 answer
  • 6 1/16 in decimal form
    9·2 answers
  • Did I get it correct?
    10·2 answers
  • Determine if the following is true: if sin^2x cos^2x=1, then sinx+cosx=1
    14·1 answer
  • Solve for x. 206-x= 133​
    8·2 answers
  • The perimeter of AXYZ is __<br> units
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!