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Lynna [10]
3 years ago
9

Rearrange this for z

Mathematics
2 answers:
Ahat [919]3 years ago
8 0

4z^3=\frac{(x^{1/2}y^{-3}z)^2}{y-s}=\frac{(x^{1/2}y^{-3})^2z^2}{y-s}\\4\frac{z^3}{z^2}(=4z)=\frac{(x^{1/2}y^{-3})^2}{y-s}\\z = \frac{(x^{1/2}y^{-3})^2}{4(y-s)}

xz_007 [3.2K]3 years ago
4 0

Answer:

z = x/[4y⁶(y - 8)]

Step-by-step explanation:

Distribute the powers

4z³ = (x × y^-6 × z²)/(y - 8

Divide both sides by 4z²

z = (x × y^-6)/4(y - 8)

z = x/[4y⁶(y - 8)]

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