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Lynna [10]
3 years ago
9

Rearrange this for z

Mathematics
2 answers:
Ahat [919]3 years ago
8 0

4z^3=\frac{(x^{1/2}y^{-3}z)^2}{y-s}=\frac{(x^{1/2}y^{-3})^2z^2}{y-s}\\4\frac{z^3}{z^2}(=4z)=\frac{(x^{1/2}y^{-3})^2}{y-s}\\z = \frac{(x^{1/2}y^{-3})^2}{4(y-s)}

xz_007 [3.2K]3 years ago
4 0

Answer:

z = x/[4y⁶(y - 8)]

Step-by-step explanation:

Distribute the powers

4z³ = (x × y^-6 × z²)/(y - 8

Divide both sides by 4z²

z = (x × y^-6)/4(y - 8)

z = x/[4y⁶(y - 8)]

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Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
3 years ago
“the perimeter of the rectangle below is 90 units. find the length of side PS. write your answer without variables.”
Rzqust [24]

Answer:

19

Step-by-step explanation:

The opposite sides are equal, so:

PS = 3y+1

RS = 4y+2

QR = 3y+1

PQ = 4y+2

Therefore, we can set the perimeter 90 = PS+RS+QR+PQ

90 = (3y+1) + (4y+2) + (3y+1) + (4y+2), or,

90 = 2(3y+1) + 2(4y+2)

90 = 6y+2 + 8y+4

90 = 14y + 6

84 = 14y

y = 6

Then, we go back to the question. It's asking for the length of PS. PS = 3y+1, so we plug in 6 for y

3(6)+1

18 + 1 = <u>19</u>

5 0
3 years ago
daniel’s print shop purchased a new printer for 35,000 each year it depreciates at a rate of 5% how much will the printer be wor
frutty [35]

Answer:

$23,219.72

Step-by-step explanation:

ab^x

a: initial value

b: value remaining after depreciation per year (in percentage)

x: number of years that have passed

35000(0.95)^8= 23219.7151

Round to the nearest hundredth value:

About $23219.72

4 0
3 years ago
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