The true question should be like this:
<span>What is the center and radius of the following circle: x^2 + (y _ 6)^2 = 50,
circle quation formula is (x-a)^2 + (y-b)^2 = R², so by identifying each term, we find </span>(x-a)^2=x^2 = (x-0)^2, (y-b)^2= (y _ 6)^2, R² = 50, implies R =5sqrt(2),
it is easy to identify that the center is (a,b)= (0, 6)
the radius is R =5sqrt(2),
The first term(a1) is 3
The second term (a2) is obtained by multiplying 3*(-5)
The third term A3 by multiplying 3 * -5 -5 = a2 times -5
Than you go on and one with that
But your answer is
A1=3;an+1=an(-5)
The answer is 5/7. That is the answer :)
Answer:
if -5n+7<57, then n>-10.
if 6n+2<8, then n<1.
Step-by-step explanation:
-5n+7<57
1. subtract 7 from both sides:
-5n+7 -7< 57 -7
-5n<50
2. divide both sides by -5 (remember to flip the sign whenever you divide by a negative number):
-5n ÷-5<50 ÷-5
n>-10
6n+2<8
1. subtract 2 from both sides:
6n+2 -2<8 -2
6n<6
2. divide both sides by 6:
6n ÷6<6 ÷6
n<1
