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Juli2301 [7.4K]
3 years ago
15

Review the graph of y = sin(x). Based on the graph, what are the domain and range of the sine function? Y 3+ 2+ domain: [0, 2TT)

; range: [-1, 1] O domain: (-1, 1); range: [0, 2TT) domain: (-1, 1); range: (-0, 0) domain:(-0, 0); range: [-1, 1] I JT 57 Зл 4 Зл 7л 2 2 4 -1+ -2+ -3+​

Mathematics
1 answer:
fgiga [73]3 years ago
3 0

Answer:

The right answer is domain: (-∞, ∞); range: [-1, 1] ⇒ D

Step-by-step explanation:

In any function,

Domain is the values of x

Range is the values of y corresponding to x

In the function y = sin(x),

∵ The graph ends with arrows

→ That means there is many cycle not 1 cycle

∴ x ∈ R

→ That means x can be any value from -∞ to ∞

∵ x is the domain of the function

∵ R is the set of real numbers

∴ Domain = {x : x ∈ R} = (-∞, ∞)

∵ sin(\frac{\pi}{2}) = 1

∵ The greatest value of y is 1 at x = \frac{\pi}{2}

∵ sin(\frac{3\pi}{2}) = -1

∵ The smallest value of y is -1 at x = \frac{3\pi}{2}

∴ -1 ≤ y ≤ 1

∵ y is the range of the function

∴ Range = {y : -1 ≤ y ≤ 1} = [-1, 1]

∴ The right answer is domain: (-∞, ∞); range: [-1, 1]

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Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.
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Answer:

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Step-by-step explanation:

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Proof:

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