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deff fn [24]
3 years ago
12

Patrick is building a sandbox he begins with one piece of wood. He cuts 3 feet off the piece of wood then he cuts the remaining

length of wood into four equal parts if each part is 5 feet long what was the original length of the piece of wood
Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer: the original length of the piece of wood is 23 feet

Step-by-step explanation:

Let x represent the original length of the piece of wood.

He cuts 3 feet off the piece of wood. This means that the remaining length of wood would be

(x - 3) feet

he cuts the remaining length of wood into four equal parts. if each part is 5 feet long, it means that

(x - 3)/4 = 5

Cross multiplying by 4, it becomes

x - 3 = 4 × 5

x - 3 = 20

x = 23

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3•-13/8 is -4.875 or or -4 7/8
8 0
2 years ago
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Evaluate another function please
kari74 [83]

Answer:

70, I think

Step-by-step explanation:

f(10)= -10^2- 3(10)

f(10)= 100-30

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6 0
2 years ago
enrollment in the ski/snowboard club increased by 30% this year. there are now 182 students in the club. how many students were
eduard
Enrolement increased by 30% that means last year=100%
incease of 30%=30+100=130% now

now=182

percent means parts out of 100 so
130%=130/100=13/10


182=13/10 of x (x represents the number last year)
of means multipy so
182=13/10 times x
multiply both sides by 10/13 to clear fraction
182 times 10/13=x=140



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8 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 < T < 36 , where T is
antoniya [11.8K]

Answer:

N(T(t)) = 1408t^2 - 385.6t - 105.52

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

N(T(t)) = 22 * (8t + 1.7)^2  - 123 * (8t + 1.7) + 40

N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40

N(T(t)) = 1408t^2 + 598.4t + 63.58 -  984t - 169.1

N(T(t)) = 1408t^2 - 385.6t - 105.52

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

8019 = 1408t^2 - 385.6t - 105.52

1408t^2 - 385.6t - 8124.52 = 0

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0
3 years ago
What is the percent of 1.6 hours to 0.95 hour
Stolb23 [73]
1.6*100/0.95=168%     1.6 to 0.95
0.95*100/1.6=59%       0.95 to 1.6
7 0
3 years ago
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