All categories

3 years ago

Can someone help me out I will give out brainly

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

7 0

Answer:

x = 2

Perimeter = 22 cm

Area = 21 cm²

Step-by-step explanation:

=> We know that the 2 side lengths of the given triangle are congruent, because of the congruency mark theorems, therefore to solve for x first, we can say;

6x - 4 = 8

6x = 8 + 4

6x = 12

x = 12/6

Now that we know the side lengths of the triangles are 8, 8 and 6, we can find the perimeter;

Side 1 + Side 2 + Side 3 = Perimeter

8 + 8 + 6 = Perimeter

<u>22 = Perimeter</u>

Lastly to find the Area of the triangle, follow the formula of;

A = 1/2 (b * h)

A = 1/2 (6 * 7)

A = 1/2 (42)

Hope this helps!

Luda [366]3 years ago

4 0

Answer:

x = 2, P = 22 cm, A = 21 cm²

Step-by-step explanation:

The 2 legs of the triangle are congruent , then

6x - 4 = 8 ( add 4 to both sides )

6x = 12 ( divide both sides by 6 )

x = 2

perimeter = 8 + 8 + 6 = 22 cm

Area = $\frac{1}{2}$ bh ( b is the base and h the perpendicular height )

Here b = 6 and h = 7 , then

A = $\frac{1}{2}$ × 6 × 7 = 3 × 7 = 21 cm²

You might be interested in

Algebra II Help??? Subtracting Fractions<br><br> (2x)/(y^2-x^2) - (x)/(y-x)

denis23 [38]

Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
$\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}$ =
$\frac{2x-x(x+y)}{y^2-x^2}$ =
$\frac{2x-x^2-xy}{y^2-x^2}$

4 0

3 years ago

If m angle B=m angle D=34 , A what must m angle C be to prove quadrilateral ABCD is a parallelogram?

eimsori [14]

A is the answer
180-34= 146

7 0

3 years ago

Micheala drives 825 miles to Cali the trip takes her 17 hours she uses 38 gallons of gas on the trip which costs her $125 find h

In-s [12.5K]

48.53 mph
21.71 MPG
$3.29 per gallon

8 0

3 years ago