Ask question

Ask question

All categories

Anastaziya [24]

3 years ago

8

amanda has certain amount of money if she spends 12$ then she has 1/5 of the original amount left how much money did she have or

iginally.

2 answers:

Ede4ka [16]3 years ago

8 0

Answer:

60

Step-by-step explanation:

12 = 1/5

12 x 5 = 60

Archy [21]3 years ago

4 0

Answer:

60

Step-by-step explanation:

12 × 5 = 60

You might be interested in

Jasmine painted flowers in art class. She painted 5 daisies, 7 pink roses, and 3 tulips.

andreyandreev [35.5K]

Answer:

15 flowers

Step-by-step explanation:

7+3=10

10+5=15

7 0

2 years ago

Read 2 more answers

Trig question easy answer for 15 points

sattari [20]

Answer:

$x = \boxed{10}$

Step-by-step explanation:

$\sin(60) = \frac{x}{12} \\ x = 12 \sin(60) \\ x = 12(0.8660254038) = 10.4$

4 0

2 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

Find the surface area of each figure. Round answers to two decimal places. Use 3.14 for pi

ELEN [110]

Answer:

the top wpuld be 73.14 and i cant see the numbers at the bottom

Step-by-step explanation:

8 0

3 years ago

Choose the correct answer choice please show steps!!

sladkih [1.3K]

Answer:

$\large\boxed{B.\ \cos(37^o)=\dfrac{x}{14}}$

Step-by-step explanation:

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\\text{We have}\ adjacent=x\ \text{and}\ hypotenuse=14.\\\text{Therefore it's a cosine.}$

6 0

2 years ago