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Gnom [1K]
2 years ago
5

What is the inverse of the function? f(x)=3^x−1

Mathematics
1 answer:
geniusboy [140]2 years ago
7 0

y = f(x) = 3^{x} - 1

let x be y and y be the x, so we have

x = 3^{y} - 1

3^{y} = x + 1

log_{3}(3)^{y} = log_3(x + 1)

y = log_{3}(x+1)



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In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq
MAXImum [283]
<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

  • P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
  • P(B) = 20/80 = 1/4 = probability of picking someone taking French
  • P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

6 0
3 years ago
A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b
IrinaK [193]

Answer:

a. [ 0.454,0.51]

b. 599.472 ~ 600

Step-by-step explanation:

a)

Confidence Interval For Proportion

CI = p ± Z a/2 Sqrt(p*(1-p)/n)))

x = Mean

n = Sample Size

a = 1 - (Confidence Level/100)

Za/2 = Z-table value

CI = Confidence Interval

Mean(x)=410

Sample Size(n)=850

Sample proportion = x/n =0.482

Confidence Interval = [ 0.482 ±Z a/2 ( Sqrt ( 0.482*0.518) /850)]

= [ 0.482 - 1.645* Sqrt(0) , 0.482 + 1.65* Sqrt(0) ]

= [ 0.454,0.51]

b)

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)

Z a/2 at 0.05 is = 1.96

Samle Proportion = 0.482

ME = 0.04

n = ( 1.96 / 0.04 )^2 * 0.482*0.518

= 599.472 ~ 600

8 0
3 years ago
Unit 3 homework 6 Gina Wilson
Sonja [21]

Answer:

5) The equation of the straight line is   2 x - y + 1 =0

6) The equation of the straight line is   x + y -5 =0

7) The equation of the straight line is   5 x + 6 y - 24 =0

8) The equation of the straight line is  x - 4 y -4 =0

9) The equation of the parallel line is 3x + y -19 =0

Step-by-step explanation:

5)

The equation of the straight line is

                         y - y_{1}  = m ( x - x_{1} )

          Slope of the line

                      m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

        Given points are (1,3) , ( -3,-5)

         m = \frac{-5-3  }{-3-1 } = \frac{-8}{-4} = 2

The equation of the straight line is

                         y - y_{1}  = m ( x - x_{1} )

                        y - 3 = 2 ( x - 1 )

                        y = 2x - 2 +3

                       2 x - y + 1 =0

The equation of the straight line is   2 x - y + 1 =0

  6)

The equation of the straight line is

                         y - y_{1}  = m ( x - x_{1} )

          Slope of the line

                      m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

        Given points are (1,4) , ( 6,-1)

         m = \frac{-1-(4)  }{6-1 } = \frac{-5}{5} = -1

The equation of the straight line is  

                         y - y_{1}  = m ( x - x_{1} )

                        y - 1 = -1 ( x - 4 )

                        y - 1 = - x +4

The equation of the straight line is   x + y -5 =0

7)

The equation of the straight line is

                         y - y_{1}  = m ( x - x_{1} )

          Slope of the line

                      m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

 Given points are (-12 , 14) , ( 6,-1)

         m = \frac{-1-(14)  }{6+12 } = \frac{-15}{18} = \frac{-5}{6}

         y - 14  = \frac{-5}{6}  ( x - (-12) )

       6( y - 14 ) = - 5 ( x +12 )

      6 y - 84 = - 5x -60

       5 x + 6 y  -84 + 60 =0

      5 x + 6 y - 24 =0

8)

The equation of the straight line is

                         y - y_{1}  = m ( x - x_{1} )

          Slope of the line

                      m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

Given points are (-4 , -2) , ( 4 , 0)

              m = \frac{0+2}{4 +4}  = \frac{2}{8} = \frac{1}{4}

           y - (-2)  =\frac{1}{4} ( x - (-4) )

             4 ( y + 2) = x + 4

                x - 4 y -4 =0

  9)

The equation of the line y = 3x + 6  is parallel to the line

3x + y + k =0 is passes through the point ( 4,7 )

⇒   3x + y + k =0

⇒    12 + 7 + k =0

⇒    k = -19

The equation of the parallel line is 3x + y -19 =0

     

4 0
2 years ago
Liliana wants to determine the height of an enlarged photo that she plans to frame. The original photo was 11 inches wide by 14
vova2212 [387]

For this case, the first thing we must do is find the scale factor.

For this, we use one of the dimensions. We will use the width of the photo.

We have then:

k = \frac {132} {11}\\k = 12

Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.

We have then:

14k = 14 (12) = 168

Answer:

the new height will be:

d.168 inches


6 0
3 years ago
Read 2 more answers
I did 3 over 7 then 8 over x. I'm getting decimals. ‍♀️
julia-pushkina [17]

Answer:

The length of side <em>b</em> is 9.

Step-by-step explanation:

Triangles are similar if they have the same shape, but can be different sizes.

When two figures are similar, the ratios of the lengths of their corresponding sides are equal.

If you know that two objects are similar, you can use proportions and cross products to find the length of an unknown side. We know that the triangle ABC is similar to the triangle XYZ. Therefore the following relation must be true:

                                                      \frac{AB}{AC} =\frac{XY}{XZ}

We know that side AB is equal to 8, side AC is equal to <em>b, </em>side XY is equal to 2\frac{2}{3}, and side XZ is equal to 3.

Substituting these values into the above relation and solving for <em>b</em> we get that:

\frac{8}{b} =\frac{2\frac{2}{3} }{3}\\\\\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{2}{3}=\frac{8}{3}\\\\\frac{8}{b}=\frac{\frac{8}{3}}{3}\\\\8\cdot \:3=b\frac{8}{3}\\\\24=b\frac{8}{3}\\\\8b=72\\\\b=9

5 0
3 years ago
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