0x + 1y = -5 is the standard form of equation
<em><u>Solution:</u></em>
Given that we have to write the equation of line passing thorugh (6, -5) and has slope 0
<em><u>The equation of line in slope intercept form is given as:</u></em>
y = mx + c ---------- eqn 1
Where, "m" is the slope of line and "c" is the y - intercept
Given that, m = 0
Given point is (6, -5)
<em><u>To find the y - intercept:</u></em>
<em><u>Substitute (x, y) = (6, -5) and m = 0 in eqn 1</u></em>
-5 = 0(6) + c
c = -5
<em><u>Substitute c = -5 and m = 0 in eqn 1</u></em>
y = 0x + (-5)
y = -5
<em><u>The standard form of equation is given as:</u></em>
The standard form of an equation is Ax + By = C
In this kind of equation, x and y are variables and A, B, and C are integers
y = -5
0x + 1y = -5 is the standard form of equation
