Answer:
1.3, 1.6, 1.9
Step-by-step explanation:
Add .3 each time
Answer:
W = 2747,1 [J]
Step-by-step explanation:
Chain is 64 meters long with mass 24 Kg
Then weight of the chain is p = 24 * 9.8
p = 235.2 [N] N = kg*m/s²
And by meter is 235,2 / 64 = 3.675
Total work has two component
- work to lift the 13 top meters of chain W₁
W₁ = ∫₀ᵇ F(y) dy
- work to lift last ( 64 - 13 ) meters 51 W₂
W₂ = 3.675 * 51 * 13 Kg m² /s² [J]
W₂ = 2436,53 [J]
We need to calculate W₁
W₁ = ∫¹³₀ mgy dy ⇒ W₁ = ∫¹³₀ 3,675 ydy
W₁ = 3,675* ∫¹³₀ ydy W₁ = 3,675* y²/2 |₀¹³
W₁ = 3,675* 84,5 [J]
W₁ = 310,54 [J]
And total work W
W = W₁ + W₂
W = 310,54 + 2436,53 [J]
W = 2747,1 [J]
Step-by-step explanation:
second one because
only x+2y=8 passes through the point (2,3)
the proof is 2+2*3=2+6=8
if we replace the given point to the other equations we will take wrong results for example
first equation
x+2y=4. 2+2*3=2+6=8 that is not equal to 4
11a:
3x+5=5x-57
3x-5x=-57-5
-2x=-62
x=31
11b:
2x+2x+4x+150+4x+150=360
12x+300=360
12x=360-300
12x=60
x=5
hope this helped !!
Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)
sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)
cos(α) = adjacent/hypotenuse
= 1/sqrt(3)
now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
