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zepelin [54]
3 years ago
12

A fleet of vehicles is comprised of 60 vans, 20 limos, and X sedans. If 10% of all vehicles are limos, how many sedans are in th

e fleet?
Mathematics
2 answers:
Jlenok [28]3 years ago
7 0

Answer:

120 sedans are in the fleet.

Step-by-step explanation:

A fleet of vehicles is comprised of 60 vans, 20 limos and X sedans.

It is given that 10% of all vehicles are limos.

Let all vehicles be n

10% × n = 20

0.10n = 20

n = \frac{20}{0.10}

n = 200

Now we have to calculate the number of sedans.

So  60 vans + 20 limos + x sedans = 200

80 + x = 200

x = 200 - 80

x = 120

Therefore, 120 sedans are in the fleet.

xz_007 [3.2K]3 years ago
4 0
10% of all the cars is 20 limos.

20 * 10 = 200 cars total.

limos + vans + sedans = total cars
200 cars total - 20 limos - 60 vans = x sedans

x = 120 sedans
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Blanca jogged 8 days last month she jogged 1.25 miles on each day and burned 140 calories per mile while jogging how many calori
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Step-by-step explanation:

Bianca is said to have jogged km 8 days, while also completing 1.25 miles every day. First, we calculate the total number of miles Bianca jogged in total, and that is

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Therefore, Bianca jogged a total of 10 miles the previous month.

Again, it is said that Bianca burned 140 calories per each mile she jogged and were asked to find the total calories that was burnt.

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Step-by-step explanation:

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For carolina's birthday her mom took her and her friends to a water park.Carolina mom paid 42.50 for 5 students tickets. What wa
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
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