There are
.. floor(200/6) = 33 multiples of 6
in the range 1 .. 200.
There are
.. floor(200/15) = 13 multiples of 15
in the range 1 .. 200, half of which are also multiples of 6.
So, there are 33 +13 -6 = 40 numbers in the range 1 .. 200 that are multiples of either 6 or 15 or both.
The remaining 200 -40 = 160 numbers are not multiples of either.
Answer:
y^5/12
Step-by-step explanation:
y ^ 1/4 * y ^ 1/2
-------------------------
y ^ 1/3
We know a^b * a^c = a^(b+c)
y^ 1/4 * y^1/2 = y^ (1/4+1/2) = y^(1/4+2/4) = y^(3/4)
y ^ 3/4
---------
y ^ 1/3
We know a^b / a^c = y(b-c)
y^(3/4 - 1/3) = y^(9/12 - 4/12)
y^5/12
30% change Hope this helps :)
Ok so we know that each combo meal is $5. So 24 x 5 = $120
$6 service charge has to be divided by 120.
6/120 = 0.05
5%