Answer:f i’m pretty sure
Step-by-step explanation:
Answer:
19.9875 feet
Step-by-step explanation:
The formula is given as:
Shadow of the student/Height of the student = Shadow of the telephone pole/Height of the telephone pole.
1 inch = 0.0833 feet
Shadow of the student = 5ft
Height of the student = 5 feet 4 inches
4 inches to feet
= 4 × 0.0833 feet
= 0.33 feet
Hence: Height of the student = 5 + 0.33 = 5.33 feet
Shadow of the telephone pole = 18 feet 9 inches long
9 inches to feet
= 9 × 0.0833 feet
= 0.75 feet
Hence: Shadow of the telephone pole = 18 + 0.75 = 18.75 feet
Height of the telephone pole= x
Therefore:
5/5.33 = 18.75/x
Cross Multiply
5x = 5.33 × 18.75
x = 5.33 × 18.75/5
x = 19.9875 feet
The height of the telephone pole = 19.9875 feet
Multiply both sides by 19 to get w=171
EHRP, EHFG, EFPQ Does that make sense?
Answer: Ix - 950°C I ≤ 250°.
Step-by-step explanation:
Ok, the limits are:
700°C to 1200°C.
The first step is to find the mean these numbers:
M = (700°C + 1200°C)/2 = 950°C
Now let's find the distance between the mean and the limits (which is equal to half the difference between our numbers)
D = (1200°C - 700°C)/2 = 250°C.
Now we can write our relation as:
Ix - MI ≤ D
Ix - 950°C I ≤ 250°.
if x = 1200°C.
I1200°C - 950°CI = 250°C ≤ 250°C ---- true.
if x = 700°C
I700°C - 950°CI = I-250°CI = 250°C ≤ 250°C ---- true
