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3 years ago

What is the area of the figure?

Mathematics

1 answer:

sattari [20]3 years ago

8 0

1) Find the area of the circle: Ac = pi*(2 ft)^2 = 4pi ft^2
2) Multiply this result by 3/4: (3/4)(pi)(4ft^2) = 3 pi ft^2
3) Find the area of the square: As = (2 ft)^2 = 4 ft^2
4) Add together the results of steps (2) and (3): 3 pi + 4 ft^2 (answer)

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Find the value (18 9) / 3d for d=3

Alexeev081 [22]

Assuming that you ment- (18*9)/3d where d=3 you would follow PEMDAS-
Parentheses
Exponents
Multiplication-Division (in order from right to left)
Addition-Subtraction (in order from right to left)
1. Parentheses- (18*9)=162
2. Solve your variables- 3d (3*3)=9
Giving you- 162/9
3. Solve-162/9=18

7 0

3 years ago

A total of 50,000 contestants are chosen for a survey. A

ankoles [38]

I am pretty sure it is linear decrease,

4 0

3 years ago

The latest poll from ESPN asked fans what their favorite sport was, considering pro, college and highschool levels. Out of 1000

shepuryov [24]

Answer:

Confidence interval is $0.2911$

Step-by-step explanation:

Given that 32% of fans sport is basketball as favorite sport. So total number of fans is,

$32\%\times 1000$

$= \dfrac{32}{100}\times 1000$

$=320$

So 320 fans favorite sport is basket ball.

Now find sample proportion ,

$\widehat{p}=\dfrac{number\:of\:people\:in\:the\:sample}{total\:number\:of\:people}$

Substituting the value,

$\widehat{p}=\dfrac{320}{1000}$

$\widehat{p}=0.320$

Formula for confidence interval is,

$CI=\widehat{p}\pm z\sqrt{\dfrac{\widehat{p}\left (1-\widehat{p}\right )}{n}}$

To calculate the z value.

$Confidence Level=1-\alpha$

$0.95=1-\alpha$

$0.05=\alpha$

Now divide above value by 2,

$\dfrac{0.05}{2}=\dfrac{\alpha}{2}$

$0.025=\dfrac{\alpha}{2}$

To find the value of z score calculate the area under the curve as follows

$A=\dfrac{1+CL}{2}$

$A=\dfrac{1+0.95}{2}$

$A=\dfrac{1.95}{2}$

$A=0.975$

On z table, find the value of 0.975. So the row corresponding to 0.975 is 1.9 and column corresponding to 0.975 is 0.06. Adding these two values the z score is 1.96.

or find the value from excel by using command as follows,

=NORM.S.INV(0.025)= -1.959963985

Now substituting the value,

$CI=0.320\pm 1.96\sqrt{\dfrac{0.320\left (1-0.320\right )}{1000}}$