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Alik [6]
3 years ago
11

I don’t understand what I’m suppose to do. Can someone please help?

Mathematics
1 answer:
Ksju [112]3 years ago
3 0

From the 64 values in the table on the left, count how many fall within the given ranges under the "classes" column in the table on the right. The "frequency" is the number of values in the data that belong to a given "class".

For example, "< -16.0" means "values below -16.0". Only one number satisfies this: -16.2 (first row, third column). So the frequency for this class is just 1.

Then for the range "-15.9 - 13.0", which probably means "numbers between 15.9 and -13.0, inclusive", the frequency is 0 because every number in the table is larger than the ones in this range.

And so on.

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$5000 at 6% for 9 months what is the balance
Kay [80]
I think it's suppose to go

6% is .06 divided by 12 which is .005 times the number of months so in this case 9 so 5,000 times .005 times 9 which is 225 so 5,000 plus an interest of 225 adds up to 5,225
8 0
3 years ago
Read 2 more answers
If the revenue for the week is $2000, and labor cost consist of two workers earning $8 per hour who works 40 hours each, whay is
SVEN [57.7K]
Two workers earning 8 bucks an hour for 40hrs, well, that means each worker is making 8*40 or 320 bucks, now, is two workers, so 320+320 or 640 is the total cost then.

now, the revenue, sales income, is 2,000 bucks, how much is 640 off of?

well, if we take 2000 to be the 100%, what is 640 in percentage off of it?

\bf \begin{array}{ccllll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;2000&100\\&#10;640&x&#10;\end{array}\implies \cfrac{2000}{640}=\cfrac{100}{x}

solve for "x".
6 0
3 years ago
Could you please help with this question for domain, range, and end behavior? I started it, but I think I'm doing it wrong.
Tanzania [10]

It looks like you have the domain confused for the range! You can think of the domain as the set of all "inputs" for a function (all of the x values which are allowed). In the given function, we have no explicit restrictions on the domain, and no situations like division by 0 or taking the square root of a negative number that would otherwise put limits on it, so our domain would simply be the set of all real numbers, R. Inequality notation doesn't really use ∞, so you could just put an R to represent the set. In set notation, we'd write

\{x\in\re\mathbb{R}\}

and in interval notation,

(-\infty,\infty)

The <em>range</em>, on the other hand, is the set of all possible <em>outputs</em> of a function - here, it's the set of all values f(x) can be. In the case of quadratic equations (equations with an x² term), there will always be some minimum or maximum value limiting the range. Here, we see on the graph that the maximum value for f(x) is 3. The range of the function then includes all values less than or equal to 3. As in inequality, we can say that

f(x)\leq3,

in set notation:

\{f(x)\in\mathbb{R}\ |\ f(x)\leq3\}

(this just means "f(x) is a real number less than or equal to 3")

and in interval notation:

(-\infty,3]

8 0
3 years ago
1. A ladder that has a length of 50 ft leans
ddd [48]
35 ft is the answer
7 0
3 years ago
Simplify (2/9)^3<br> A.6/9<br> B.8/729<br> C.2/720
saw5 [17]

<u>Answer:</u>

\frac{8}{729}


<u>Explanation:</u>

Before we begin, remember that:

(\frac{a}{b})ⁿ = \frac{a^n}{b^n}


This means that power is distributed in case of division


The given is:

(\frac{2}{9} )^3


Applying the above rule, we would get:

(\frac{2}{9} )^3 = \frac{2^3}{9^3} = \frac{2*2*2}{9*9*9} = \frac{8}{729}


Hope this helps :)


8 0
3 years ago
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