Given that 6RSB ~ 6ZQM, list the three pairs of congruent angles and state the three equal ratios of

One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.

Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both = $ 39

I.e 2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = $\frac{39}{6}$ = $\frac{13}{2}$

∴ sw = $\frac{13}{2}$ × $\frac{3}{2}$

or, sw = $\frac{39}{4}$

Now, the ratio of the amount for swordfish to the amount of salmon = $\frac{\frac{39}{4}}{\frac{13}{2}}$

I.e The ratio = $\frac{6}{4}$

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0

3 years ago

Please help me with this math problem??

Kazeer [188]

Answer:

37.5

Step-by-step explanation:

the triangle is enlarged by a factor of 2.5 so you multiply all of the numbers in XYZ by 2.5 then add them

15+10+12.5=37.5 units

6 0

3 years ago

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What number is 15 less than 63?

wariber [46]

Answer:

48

Step-by-step explanation:

4 0

2 years ago

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The A&M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a

Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0

2 years ago

Mr. Valdez puts $10,000 in a retirement account and does not make any deposits or withdrawals. The table below shows the amount

Maurinko [17]

Answer:

f(x)= 9,974.73 (1.05)x

7 0

3 years ago

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