the question does not present the options, but this
does not interfere with the resolution
Let
a1=-4
a2=-24
a3=-144
a4=-864
a5=?
we know that
a2/a1=-24/-4----> 6-------> a2=6*a1
a3/a2=-144/-24---> 6-----> a3=6*a2
a4/a3=-864/-144---> 6----> a4=6*a3
therefore
a5=6*a4-----> a5=6*(-864)------> a5=-5184
hence
the formula is
an=6*a(n-1)
<span>n and (n-1) are subscripts </span>
Answer:
364.8 ft^2.
Step-by-step explanation:
I assume you want the area of the figure.
Total area = area of the top triangle + area of the trapezium
= 1/2 * base * height + 1/2 * height * ( sum of the parallel sides)
= 1/2 * 18 * 6 + (14/2)( 18 + 26.4)
= 54 + 310.8
= 364.8 ft^2.
Answer:
The Median of this data is 17 :)
Step-by-step explanation:
The slope would be -1 since it’s the coefficient of -x
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²
