Answer:
1
Step-by-step explanation:
What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second?
3 consecutive angles
= x, x + 1, x + 2
We are told in the question that:
the sum of the first and third is equal to three times the second
a + c = 3b
x + x + 2 = 3(x + 1)
2x + 2 = 3x + 3
3x - 2x = 2 - 3
x = -1
The largest of the three numbers is the third number
= x + 2
x = -1
x + 2 = -1 + 2
The third and largest number is 1
Setting AC = BD because the diagonals are congruent, then 3y/5 = 3y -4
y=5/3
So then AC = 1 = BD
F(x) = 5x
for f(7) you replace x with 7 so it will be : f(7) = 5(7) = 35
Answer:
yes
Step-by-step explanation:
side 1
(2,8) to (2,2)
8-2 = 6 (length of this side)
side 2
(2,2) to (-4,2)
2-(-4) = 6
side 3
(-4,2) to (-4,8)
8-2 = 6
side 4
(-4,8) to (2,8)
2- (-4) = 6
* note: it doesn't matter the order of subtraction because length can't be negative (so just make sure your answer is positive) , also don't subtract the side that is constant, you will get 0, a side can not be 0 cm
to find the area of a square multiply length by width
6 x 6 = 36
5. The answer is D
because it says no more than 160 so it's possible to be equal to 160.
6.
So the answer is A
