343^1/3
=(7)^3*1/3 [ 3 and 3 are cancelled]
=7
Answer:
x=2;DE,EF=9,DF=5
Step-by-step explanation:
Since DEF is isoceles, you can set the equations
x+7 and 2x+5 equal to each other
x+7=2x+5, now solve for x
-x=-2,
x=2, now plug in for each side
DE,EF=9
DF=3(2)-1=5
I'm not sure exactly what it is but it would be a negitive
Incomplete question please add a image
To solve for X in this equation, you would subtract both sides by 14 because our goal is to get X on its own. If we write it out, we see that
X + 14 - 14 = 56 - 14
X=42
Because we have a positive 14, a negative 14 will average out to be 0, but what you do to one side, you must do to the other.
If you have any more questions, feel free to ask!
