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charle [14.2K]
3 years ago
5

PLEASE HELP!! 40 PTS

Mathematics
2 answers:
sasho [114]3 years ago
4 0

Answer:

y ≤ −2x + 3

y ≤ x + 3

Step-by-step explanation:

they both share the slope of 3.

line a has a slope of -2

line b has a slope of 1

the sign ≤ means that the inequalities have a solid line and there below the line.

please mark brainliest :)

vichka [17]3 years ago
4 0

Answer: y ≤ −2x + 3

y ≤ x + 3

Step-by-step explanation:

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A ailen maked that thats cazy

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  • Answer:

<em>429 cm²</em>

  • Step-by-step explanation:

<em>A(blue) =</em>

<em>= 2×6cm×10cm + 2×6cm×8cm + 8cm×10cm + (8cm×10cm - 5cm×4cm)</em>

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QUESTION 1
SVEN [57.7K]

Answer:

1)

1st Error: In going from Step 3 to Step 3.

Reason: Negative sign is not distributed inside the brackets.

2nd Error: In going from Step 5 to Step 6

Reason: Sign of the number is not changed while moving to other side of inequality,

2)

a) 12=-4(-6x-3) and x+5=-5x+5

b) -(7-4x)=9 and 5x+34=-2(1-7x) and -8=-(x+4)

Step-by-step explanation:

Question 1)

The given inequality is:

\frac{5}{12}-\frac{x-3}{6} \leq  \frac{x-2}{3}

<u>Step 1: Making the denominators common for all fractions</u>

\frac{5}{12}-\frac{2}{2} \times \frac{x-3}{6} \leq \frac{4}{4} \times \frac{x-2}{3}

This step is done correctly in the given solution.

<u>Step 2: Simplifying </u>

\frac{5}{12}-\frac{2x-6}{12}\leq \frac{4x-8}{12}

This step is done correctly in the given solution

<u>Step 3: Multiplying both sides by 12, and simplifying.</u>

5-(2x-6)\leq 4x-8\\\\ 5-2x+6\leq 4x-8

First error is made in this step. While opening the brackets, the negative sign should be distributed inside the bracket, which will change the signs.

<u>Step 4: Simplification:</u>

11-2x\leq 4x-8

<u>Step 5: Moving Common terms to one side and simplifying</u>

-2x-4x\leq -8-11\\\\ -6x\leq -19

Error was made in this step. When a number is moved to other side, its sign will be changed.

<u>Step 6: Dividing both sides by -6</u>

x\geq \frac{19}{6}

Conclusion:

1st Error: In going from Step 3 to Step 3.

Reason: Negative sign is not distributed inside the brackets.

2nd Error: In going from Step 5 to Step 6

Reason: Sign of the number is not changed while moving to other side of inequality,

Question 2:

In the Equation 2: 12=-4(-6x-3), when -4 will be multiplied inside the brackets, the 12 on eft hand side will cancel the 12 that will appear on right hand side, giving a result that will lead to x = 0.

Same is the case with Equation 6: x+5=-5x+5, 5 on both sides will cancel out leaving x = 0.

So, 2nd and 6th equations will have the same solution.

In Equation 1, on expanding the bracket and moving 7 to other side, we get a relation: 4x = 16

In Equation 3, on simplifying the right hand side, and carrying common terms to one side, we get the relation: - 9x = -36

In Equation 5, on expanding the bracket and simplifying the relation is reduced to 4 = x

It can be observed that all these 3 equations have the same solution i.e. x = 4

So, the following set of Equations have the same solution:

a) 12=-4(-6x-3) and x+5=-5x+5

b) -(7-4x)=9 and 5x+34=-2(1-7x) and -8=-(x+4)

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