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spayn [35]
3 years ago
15

For the given value of a , find - a and |a|

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0
1.\\a=10.2\\-a=-10.2\\|a|=|10.2|=10.2\\------------\\2.\\a=-14\\-a=-(-14)=14\\|a|=|-14|=14\\-------------\\3.\\a=\frac{1}{2}\\-a=-\frac{1}{2}\\|a|=|\frac{1}{2}|=\frac{1}{2}
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The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inche
mash [69]

Answer:

6,4

Step-by-step explanation:

I'm not sure if 4 is correct but 6 definitely is. I hope this helps

3 0
2 years ago
5 pens for 4.85 what is the unit price
liraira [26]

Answer:

0.97

Step-by-step explanation:

You only have to divide 4.85 by 5 and you will get the unit price.✨ Trust me I get it right!

5 0
3 years ago
Can you guys help me to find the measure of each angle tysm.
barxatty [35]

Answer:

∠EBF = 51°

∠DBE = 17°

∠ABF = 141°

∠EBA = 90°

∠DBC = 107°

∠DBF = 68°

Step-by-step explanation:

Hope this helps

7 0
3 years ago
Read 2 more answers
create a sketch of the graph of a function whose gradient is linear and that gradient has an x-intercept at x=4
valentina_108 [34]
Here is one that meets your requirements.

7 0
3 years ago
Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

7 0
3 years ago
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