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3 years ago

What is the surface area of the cylinder with height g in and radius 4 in? Round your

Mathematics

1 answer:

zaharov [31]3 years ago

4 0

Answer:

if you want ans area of cylider is 2πrh+2πr2

Step-by-step explanation:

need thanks and make me brainiest if it helps you

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A bowl is the shape of a hemisphere and made out of thick clay. The diameter of the outside bowl is 44.6 cm. And the diameter of

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Ive already explained this somebody else asked if you find it you will have the answer

3 0

3 years ago

Use multiplication to describe the relationship between the dividend, the divisor and the quotient. Then use that relationship t

Romashka [77]

In a division problem, ...

... dividend / divisor = quotient

Multiplying both sides of this equation by "divisor", we get ...

... dividend = quotient × divisor . . . . . . . . the desired relationship

The for dividend = 1/8, divisor = 6, and quotient = 1/48, this becomes ...

... 1/8 = 1/48 × 6

... 1/8 = 6/48 = 1/8 . . . . . the given values are consistent

3 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Anna007 [38]

Answer:

To find the maximum of a function in ax^2 + bx + c form, you can use the formula: maximum = c - (b^2 / 4a).

In this question, a = -16, b = 180, and c = 63.

Maximum = 63 - (180^2/4(-16))

Maximum = 569.25

Finally, rounding this to the nearest tenth of a foot, the final answer is 569.3 ft.

Let me know if this helps!

4 0

3 years ago

Given:

lys-0071 [83]

Answer:

$PS=13\text{ units}$

Step-by-step explanation:

So, we know that PR is 20, SR is 11, and QS is 5.

We also know that PQ is perpendicular to QR, forming the right angle at ∠Q.

We know all the side lengths except for PQ and PS (the one we want to find). Notice that if we find PQ first, we can then use the Pythagorean Theorem to find PS since we already know QS.

So, let's find PQ.

We can see that we can also use the Pythagorean Theorem on PQ. PQ, QR, and PR (the hypotenuse) will be our sides. So:

$(PQ)^2+(QR)^2=(PR)^2$

We know that PR is 20.

QR is the combined length of QS+SR, so QR is 5+11 or 16.

So, substitute:

$(PQ)^2+(16)^2=(20)^2$

Solve for PQ. Square:

$(PQ)^2+256=400$

Subtract 256 from both sides:

$(PQ)^2=144$

Take the square root of both sides:

$PQ=12$

So, the side length of PQ is 12.

Now, we can use the Pythagorean Theorem again to find PS. Notice that PQ, QS, and PS also form a right triangle, with PS being the hypotenuse. So:

$(PQ)^2+(QS)^2=(PS)^2$

We already know that QS is 5. We also just determined that PQ is 12. Substitute:

$(12)^2+(5)^2=(PS)^2$

Square:

$144+25=(PS)^2$

Add:

$169=(PS)^2$

Take the square root of both sides:

$PS=13$

Therefore, the length of PS is 13 units.

And we're done!

7 0

3 years ago

Write an equation to represent the problem then solve the equation - the sum of two consecutive numbers is 73. What are the numb

masha68 [24]

2 consecutive numbers....x and x + 1

x + x + 1 = 73
2x + 1 = 73
2x = 73 - 1
2x = 72
x = 72/2
x = 36

x + 1 = 36 + 1 = 37

so ur numbers are 36 and 37 <==

3 0

4 years ago