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kari74 [83]
3 years ago
7

If ∠1 and ∠2 are complementary and m∠1 = 17º, what is m∠2

Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

m<2 = 73

Step-by-step explanation:

Since <1 and <2 are complementary (which means that they equal 90), all you have to do is subtract 17 from 90 to find your answer:

90 - 17 = 73

thus, m<2 = 73

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3x + y² - (xy)²<br> if x = 3 and y = -5
N76 [4]

Answer:

-191

Step-by-step explanation:

Replace variables with corresponding value.

3(3) + (-5)^2 - ((3)(-5))^2

Solve exponent.

3(3) + 25 - 225

Multiply.

9 + 25 - 225

Combine like terms.

-191

7 0
2 years ago
Read 2 more answers
What function has a zero of -5
zepelin [54]
There are infinitely many.

x+5=0
x^2-25=0
x^2+2x-15=0

again there are infinitely many
8 0
4 years ago
What is the length of a ramp whose rise is 10 feet and slope is 5/12
polet [3.4K]

Answer:

120 feet

Step-by-step explanation:

Length/height =second number in ratio (here's it is 12)

L/10=12

Therefore length will be 120

3 0
4 years ago
What is -4x+3 as an ordered pair
Aleks [24]

Answer:x= {y-3}   tell me if this is right thankyou!

                                         

7 0
2 years ago
How much more would $1000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the inte
choli [55]
\bf ~~~~~~ \textit{Compounding Continuously Interest Earned Amount}\\\\&#10;A=Pe^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to& \$1000\\&#10;r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\&#10;t=years\to &5&#10;\end{cases}&#10;\\\\\\&#10;A=1000e^{0.037\cdot 5}\implies A=1000e^{0.185}\\\\&#10;-------------------------------\\\\

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{quarterly, thus four}&#10;\end{array}\to &4\\&#10;t=years\to &5&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.037}{4}\right)^{4\cdot 5}\implies A=1000(1.00925)^{20}

compare both amounts.
8 0
3 years ago
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