Answer:
The segment is 6 units long.
Step-by-step explanation:
The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.
If two points at the ends of a straight line PQ are P(
) and Q(
), then the length of the segment PQ will be given by the formula
Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be
units. (Answer)
The energy of a photon is given by
E = h × v
where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴
Substitute 'h' and 'v' into the formula we have
E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
Volume is 1/3 bh.
11 times 12 is 132. 132 times 1/3 is 44
ANSWER : 44
It was rounded to the nearest Ten thousands.(710,430)
Hope i helped!!!!:D
The quadrilaterals are two congruent isosceles trap ezoids and a kite.
