There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
<h3>
Answer: 41 cm^2</h3>
Explanation:
Form a horizontal line as shown below (see attached image). This forms 2 separate smaller rectangles
- The bottom rectangle has area of 4*8 = 32 cm^2
- The top rectangle has area of 3*3 = 9 cm^2
The total area is therefore 32+9 = 41 cm^2
You can say "square cm" or "sq cm" in place of the "cm^2".
Answer:
98 square centimeters
Step-by-step explanation:
first find the area of the non shaded area
8x4=32
next find the area of the rectangle around it
13x10=130
and last you need to subtract the non shaded area from the rectangle around it to find the area of the shaded area
130-32=98
8x+2.50=3.50
-2.50 -2.50 subtract both sides by -2.50
8x=1
8. 8 divide both sides by 8
x=1/8
