1. A (x²-4y)³
2. ?=5
3. (x+3)(3y-5)
4. (4y+7)(5x-1)
        
             
        
        
        
Three and more points are collinear
        
                    
             
        
        
        
Answer D). 9 ft is correct
Height of the ball at a horizontal distance of 10 feet is 9 ft 
Step-by-step explanation:
A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y). 
Y(x) = 
Question asked is " What will be height (Y) of the ball when X=10 ft " 
Simply putting value of X in given equation
we get,
Y(x) = 
Y(x) = 
Y(x) = 
Y(x) = 
Y(x) = 
<em>Therefore,</em> Height of the ball at a horizontal distance of 10 feet is 9 ft 
Answer D.  9 ft is correct
 
        
             
        
        
        
Answer:
 Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.
Step-by-step explanation:
Given:
In Δ PQT
PQ = 30 ft
QT = 28 ft
TP = 20 ft
In Δ QRS
QR = 15 ft
RS = 14 ft
SQ = 10 ft
To Prove:
Δ PQT ~ Δ QRS
Proof:
First we consider  the ratio of the sides
 ..............( 1 )
            ..............( 1 )
 ..............( 2 )
            ..............( 2 )
 ..............( 3 )
            ..............( 3 )
So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

Now in Δ PQT  and Δ QRS we have

Which are corresponding sides of a similar triangle in proportion.
∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved
 
        
             
        
        
        
Answer:
Step-by-step explanation:
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