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2 years ago

{(4x+2y=6),(-2x+2y=18):} Solve by using the elimination method

Mathematics

1 answer:

Degger [83]2 years ago

4 0

Answer:

$\displaystyle [-2, 7]$

Step-by-step explanation:

You want to eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

$\displaystyle \left \{ {{4x + 2y = 6} \atop {-2x + 2y = 18}} \right.$

{½[4x + 2y = 6]

{−2x + 2y = 18

>> $\displaystyle \left \{ {{2x + y = 3} \atop {-2x + 2y = 18}} \right. \\ \\ \frac{3y}{3} = \frac{21}{3} \\ \\ \\ y = 7$

Plug this back into the system to get the x-value of $\displaystyle -2.$

I am joyous to assist you at any time.

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If 3^2x+1= 3x+5, what is the value of x? 2 3 4 6

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Answer:

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3 years ago

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4 years ago

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Point V is on line segment \overline{UW}

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Step-by-step explanation:

we know that

UW=UV+VW -----> by addition segment postulate

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3 years ago

Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start

Kamila [148]

Option B: $\frac{1}{(m-4)(m-3)}$ is the correct answer.

Explanation:

The given expression is $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$

Simplifying the expression, we have,

$\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}$

Factor the equations, $m^{2}-16\right$ and $m^{2}-9$ ,we get,

$m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)$

$m^{2}-9=m^{2}-3^2=(m+3)(m-3)$

Substituting these factored expressions in the above expression, we have,

$\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}$

Cancelling the common terms $m+3$ and $m+4$ , we get,

$\frac{1}{(m-4)(m-3)}$

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3 years ago

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