Answer:
d is greater than c, since at ![x = 0, g(x) > f(x)](https://tex.z-dn.net/?f=x%20%3D%200%2C%20g%28x%29%20%3E%20f%28x%29)
Step-by-step explanation:
We are given two exponential functions, f and g.
Since f has the higher base(3 instead of 2 in g), it increases faster, so initially, g is greater than f, and after point (p,q), f is greater than g.
The values of c and d are found when
. At this point, we have that g is greater than f, so d is greater than c.
Answer:
For the rectangle
Length=ℓ
Breadth=b
Area is 12 cm2
ℓb=12
Perimeter is 16 cm
2(ℓ+b)=16
ℓ+b=8
Substitute b=12ℓ from first equation
ℓ+12ℓ=8
ℓ2+12=8ℓ
ℓ2−8ℓ+12=0
Use quadratic formula (x=−b±√b2−4ac2a) to find ℓ
ℓ=−(−8)±√(−8)2−(4×1×12)2×1
ℓ=8±√162
ℓ=8±42
ℓ1=8+42=6
ℓ2=8−42
Step-by-step explanation:
For the rectangle
Length=ℓ
Breadth=b
Area is 12 cm2
ℓb=12
Perimeter is 16 cm
2(ℓ+b)=16
ℓ+b=8
Substitute b=12ℓ from first equation
ℓ+12ℓ=8
ℓ2+12=8ℓ
ℓ2−8ℓ+12=0
Use quadratic formula (x=−b±√b2−4ac2a) to find ℓ
ℓ=−(−8)±√(−8)2−(4×1×12)2×1
ℓ=8±√162
ℓ=8±42
ℓ1=8+42=6
ℓ2=8−42
Answer:
![f(\pi/6)=\sqrt{3}-\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=f%28%5Cpi%2F6%29%3D%5Csqrt%7B3%7D-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
Step-by-step explanation:
Given ![f(\theta )=3tan(\theta)-sin(2\theta )](https://tex.z-dn.net/?f=f%28%5Ctheta%20%29%3D3tan%28%5Ctheta%29-sin%282%5Ctheta%20%29)
As we know that ![tan(\theta )=\frac{sin(\theta )}{cos(\theta )}](https://tex.z-dn.net/?f=tan%28%5Ctheta%20%29%3D%5Cfrac%7Bsin%28%5Ctheta%20%29%7D%7Bcos%28%5Ctheta%20%29%7D)
thus we can write
\
Thus
![f(\pi/6)=\frac{3}{\sqrt{3}}-\frac{\sqrt{3}}{2}\\\\f(\pi/6)=\sqrt{3}-\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=f%28%5Cpi%2F6%29%3D%5Cfrac%7B3%7D%7B%5Csqrt%7B3%7D%7D-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5C%5C%5C%5Cf%28%5Cpi%2F6%29%3D%5Csqrt%7B3%7D-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
Answer:
ummmmm ok u wanted someone to answer
Step-by-step explanation:
also do u have any song ideas
The answer is A because You have to start at 4 then you <u>add 3 two times</u>