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Vanyuwa [196]
3 years ago
14

7x-3=3+7x infinitely many solutions step-by-step ​

Mathematics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

0=6

Step-by-step explanation:

(You will have to rearrange terms.)

7x-3=3+7x

7x-3=7x+3

(now add three to both sides.)

7x-3=7x+3

7x-3 <u>+3</u>=7x+3 <u>+3</u>

7x=7x+6

<u></u>

<u>(</u>Now subtract 7x from both sides of the equation.<u>)</u>

7x=7x+6

7x-7x=7x+6-7x

0=6

and that's how you get your answer.

I hope this helps you.     :)

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What is the value of. X in this equation<br><br> 1.54x+6.814=8.2
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The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability
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Answer:

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(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

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(1)

Let <em>Y</em> = the time taken to deliver a pizza.

The random variable <em>Y</em> follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70

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(2)

Let <em>X</em> = results of a certain blood test.

It is provided that the random variable <em>X</em> follows a Normal distribution with parameters \mu = 60 and s = 18.

The probabilities of a Normal distribution are computed by converting the raw scores to <em>z</em>-scores.

The <em>z</em>-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z

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(b)

Compute the probability that the results are less than 85 as follows:

P(X

The percentage of results less than 85 is: 0.9177\times100=91.77\%

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

P(75

The percentage of results are between 75 and 90 is: 0.1558\times100=15.58\%

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

P(20

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The percentage of results outside the range 20 to 100 is: 0.0264\times100=2.64\%

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

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