Answer:
[see below]
Step-by-step explanation:
The difference between the record high and low temperatures in Charlotte is 109℉. We are given the record low temperature of -5℉.
![h - 5 = 109](https://tex.z-dn.net/?f=h%20-%205%20%3D%20109)
Let 'h' be the high temperature.
![h-5=109\\\\h-5+5=109+5\\\\\boxed{h=114}](https://tex.z-dn.net/?f=h-5%3D109%5C%5C%5C%5Ch-5%2B5%3D109%2B5%5C%5C%5C%5C%5Cboxed%7Bh%3D114%7D)
Hope this helps.
The tan is negative in the 2nd and 4th quadrants, knowing this, the angle that equals the value that tan = 1 in the first quadrant is the tan 45° = 1, but the question restrict for 3pi/2 < theta < 2pi, so it's the same as 270° < theta < 360° (4° Quadrant), then moving the tan 45° = to this quadrant the value will be negative, tan in 4°Q = tan(360 - 45=315°) = -1.
sec theta = 1/cos theta
cos 45° =
![\sqrt{2} \div 2](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%5Cdiv%202)
cos values in 4°Q will be positives, so it doesn't change the signal.
sec 315° = 1/cos 315°
sec 315° = 1/square root (2)/2
sec 315 = 1/1 x 2/sqroot(2)
![sec \: 315 = 2 \div \sqrt{2}](https://tex.z-dn.net/?f=sec%20%5C%3A%20315%20%3D%202%20%5Cdiv%20%5Csqrt%7B2%7D%20)
![sec \: 315 = (2 \div \sqrt{2}) \: \times ( \sqrt{2} \div \sqrt{2})](https://tex.z-dn.net/?f=sec%20%5C%3A%20315%20%3D%20%282%20%5Cdiv%20%5Csqrt%7B2%7D%29%20%5C%3A%20%5Ctimes%20%28%20%5Csqrt%7B2%7D%20%5Cdiv%20%5Csqrt%7B2%7D%29)
![sec \: 315 = 2 \sqrt{2} \div 2](https://tex.z-dn.net/?f=sec%20%5C%3A%20315%20%3D%202%20%5Csqrt%7B2%7D%20%5Cdiv%202)
Answer:
a=2 b=3 c= 180 d=180 is sns
You've certainly tried hard to describe it in enough detail so that
it can be answered without seeing the diagram. Sadly, it's not
enough.
We still don't know what's tangent to what, where point 'C' is, or
how any of this relates to a circle. You'll have to figure out some
way or us to see the diagram.
Answer is -9
Multiplying by 1/4 is the same as dividing by 4
-36(1/4) = -36/4 = -9