All categories

2 years ago

If the length of segment RQ is 8, what is the length of segment PQ?

Mathematics

1 answer:

artcher [175]2 years ago

7 0

Half of 8 is 4 so it’s b

You might be interested in

Evaluate −12(−2). (1 point) 14 −14 −24 24

stepladder [879]

Answer:

-12(-2) = 24

14 - 14 - 24 + 24 = 0

Hope this answers your question!

5 0

3 years ago

Read 2 more answers

Como dividir 2 entre 72

r-ruslan [8.4K]

Tu respuesta es 36 :).

7 0

3 years ago

Pleaseeeeeeee helppppppppppppppppppppppppppppp

ankoles [38]

The first two are true and the last one is false

8 0

2 years ago

An artist is trying to choose 5 covers for children’s books. There are 10 different covers to choose from. How many ways can the

Aleksandr [31]

Answer:

252

Step-by-step explanation:

The order of the books isn't important, so we'll use combinations.

The number of ways to choose 5 books from 10 is:

₁₀C₅ = 10! / (5! (10 − 5)!)

₁₀C₅ = 10! / (5! 5!)

₁₀C₅ = 10×9×8×7×6 / (5×4×3×2×1)

₁₀C₅ = 252

5 0

2 years ago

In studies for a medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.

timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

$p = 0.03$

$q = 1 - 0.03 = 0.97$

The mean is

$\mu = np$

$\mu = 643 \times 0.03 = 19.29$

The standard deviation is

$\sigma = \sqrt{npq}$

$\sigma = \sqrt{643 \times 0.03 \times 0.97}$

$\sigma =4.33$

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

$P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 1.20) \\ = 0.051$

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

$P(X \: < \: 24.5) = P(z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P(z \: < \: 1.20) \\ = 0.8849$

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

$P(X \: > \: 10.5) = P(z \: > \: \frac{10.5 - 19.29}{4.33} ) \\ = P(z \: > \: - 2.03)$

$= 0.9788$

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

$P(23.5 \: < \: X \: < \: 28.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{28.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 2.13) \\ = 0.1494$

3 0

3 years ago