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forsale [732]
3 years ago
8

Which expression use the associative property to make it easier to evaluate 20 (3/5 × 6)

Mathematics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

D

Step-by-step explanation:

trust me :D

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Kathy deposits $25 into an investment account with an
Oksi-84 [34.3K]

Answer:

25 x 1.05^15 = $51.97

7 0
3 years ago
Will give brainliest
Sonja [21]

The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).

<h3>How to simplify the addition between two rational equations</h3>

In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:

  1. (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²)      Given
  2. (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²)     x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
  3. 1 / (n - 2) + 5 / (3 · n²)     Associative and modulative property / Existence of the multiplicative inverse
  4. [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)]       Addition of fractions with different denominator
  5. (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²)       Distributive property / Power properties / Result

To learn more on rational equations: brainly.com/question/20850120

#SPJ1

4 0
2 years ago
A sales associate farms a neighborhood with 750 homes. The owners seem to list their homes every six years. How many listings sh
jenyasd209 [6]

Answer:

50 homes

Step-by-step explanation:

Given that:

Total Number of homes = 750

Years at which home is listed = 6

Thus average listing per year = (total number of homes / years)

Average listing per year = 750 / 6

Average listing per year = 125 homes

If 40% of homes in the neighborhood can be listed :

0.4 * 125

= 50 homes

8 0
2 years ago
What is the reason that m&lt;2 and m&lt;3 are supplementary
katen-ka-za [31]

Answer:

see explanation

Step-by-step explanation:

∠2 and ∠3 are same- side interior angles and are supplementary.

6 0
3 years ago
Quadratics need help making parabola
timama [110]

Answer:

The equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4, whose real vertex is (x,y) = (2, -5.333), not (x,y) = (2, -5).

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

(x_{1}, y_{1}) = (-2, 0), (x_{2}, y_{2}) = (6, 0), (x_{3}, y_{3}) = (0, -4)

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

4\cdot a -2\cdot b + c = 0 (1)

36\cdot a + 6\cdot b + c = 0 (2)

c = -4 (3)

The solution of this system is: a = \frac{1}{3}, b = - \frac{4}{3}, c = -4. Hence, the equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4. Lastly, we must check if (x,y) = (2, -5) belongs to the function. If we know that x = 2, then the value of y is:

y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4

y = -5.333

(x,y) = (2, -5) does not belong to the function, the real point is (x,y) = (2, -5.333).

5 0
2 years ago
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