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3 years ago

What is the lateral area of the cone to the nearest whole number? The figure is not drawn to

Mathematics

1 answer:

Sveta_85 [38]3 years ago

6 0

Answer:

The lateral surface area of the cone is $25120\ m^2$ .

Step-by-step explanation:

We have.

Height of a cone is 60 m

Diameter of a cone is 10 m

Radius, r = 80 m

The lateral surface area of a cone is given by :

$A=\pi rl$

l is slant height of the cone,

$l=\sqrt{60^2+80^2} =100\ m$

Plugging all values in above formula,

$A=3.14\times 80\times 100\\\\A=25120\ m^2$

So, the lateral surface area of the cone is $25120\ m^2$ .

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Luda [366]

Answer:

a) H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

b) $\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

c) $\chi^2_{crit}=5.991$

d) Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

High school Some College Bachelor or higher Total

Public Broadcasting 15 15 10 40

Commercial stations 5 25 10 40

Total 20 40 20 80

We need to conduct a chi square test in order to check the following hypothesis:

Part a

H0: There is no association between level of education and TV station preference (Independence)

H1: There is association between level of education and TV station preference (No independence)

The level os significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part b

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{20*40}{80}=10$

$E_{2} =\frac{40*40}{80}=20$

$E_{3} =\frac{20*40}{80}=10$

$E_{4} =\frac{20*40}{80}=10$

$E_{5} =\frac{40*40}{80}=20$

$E_{6} =\frac{20*40}{80}=10$

And the expected values are given by:

High school Some College Bachelor or higher Total

Public Broadcasting 10 20 10 40

Commercial stations 10 10 20 40

Total 20 30 30 80

Part b

And now we can calculate the statistic:

$\chi^2 = \frac{(15-10)^2}{10}+\frac{(15-20)^2}{20}+\frac{(10-10)^2}{10}+\frac{(5-10)^2}{10}+\frac{(25-10)^2}{10}+\frac{(10-20)^2}{20} =33.75$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(2-1)(3-1)=2$

Part c

In order to find the critical value we need to look on the right tail of the chi square distribution with 2 degrees of freedom a value that accumulates 0.05 of the area. And this value is $\chi^2_{crit}=5.991$

Part d

And we can calculate the p value given by:

$p_v = P(\chi^2_{3} >33.75)=2.23x10^{-7}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(33.75,2,TRUE)"

Since the p value is lower than the significance level we enough evidence to reject the null hypothesis at 5% of significance, and we can conclude that we have dependence between the two variables analyzed.

7 0

3 years ago

19) Write the scientific notation of 1

mylen [45]

Answer:

1.0 x 10^0

Step-by-step explanation:

The above works because 10^0 = 1, and 1 x 1 = 1.

Brainliest, please :)

7 0

1 year ago

A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s

ANTONII [103]

<h2>Hello!</h2>

The answer is:

The ball will hit the ground after $t=2.47s$

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula. We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

We are given the function:

$h=-5t^{2}-3t+38$

Where,

$a=-5\\b=-3\\c=38$

Then, substituting it into the quadratic equation, we have:

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s$

Since negative time does not exists, the ball will hit the ground after:

$t=2.473s=2.47s$

Have a nice day!

4 0

3 years ago

Read 2 more answers

3. Ruby and Sapphire love strawberries. Ruby starts out with 10 strawberries and finds 3 more

Svetllana [295]

Answer:

4 minutes

Step-by-step explanation:

Let the time taken for them to have the same number of strawberries be x minutes.

<u>Initially</u>

Ruby: 10 strawberries

Sapphire: 30 strawberries

<u>After x minutes</u>

Ruby: (10 +3x) strawberries

Sapphire: (30 -2x) strawberries

Since we let x minutes be the amount of time that has passed when they have the same amount of strawberries,

10 +3x= 30 -2x

Bring all x terms to one side, constant to the other:

3x +2x= 30 -10

Simplify:

5x= 20

Divide both sides by 5:

x= 20 ÷5

x= 4

∴ It will take 4 minutes.

3 0

3 years ago

loyd is playing a game where he is trying to roll a 3 with a standard die. If he gets a 3 in any of his first 8 rolls, he wins;

Komok [63]

The probability would probably be 1/8

8 0

3 years ago