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joja [24]
3 years ago
10

Im checking my test. whats the answer?

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

C.

Hope this helps. :)))

vlabodo [156]3 years ago
5 0

Answer:

C

Step-by-step explanation:

It can' be B because as you go right on the x-axis (forward in time), the distance upward on y (how far walked) also goes up steadily. So that is a person walking at a steady pace, no stopping.

A is interesting.  It shows the person walked in the positive y-direction, stopped a while, and then went back the other way (negative y-direction).

C shows a person walking (in the positive y-direction), then stopping, then walking in the <u>same </u>direction some more. The probelm says they walk slower after the pause, so the slope on the second part should be less steep. I guess it is, but would it have killed them to make it a little more obvious? haha.

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What is the value of x in the drawn figure?<br>A. 45<br>B. 3<br>C. 27<br>D. 19.8<br>​
guapka [62]

Answer:

A 45

Step-by-step explanation:

45 is the answer and hope this helps!

6 0
4 years ago
Read 2 more answers
Please guys help me out with this
Kisachek [45]

When you have a negative exponent, you move the variable with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

x^{-2} or \frac{x^{-2}}{1} =\frac{1}{x^2}

\frac{1}{2y^{-3}} =\frac{y^3}{2}  (you don't move the "2" because "2" has an exponent of 1, only "y" has the negative exponent)

\frac{5^{-2}}{y}=\frac{1}{(5^2)y} =\frac{1}{25y}

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (But you can only combine the exponents when the variables are the same)

x^2(y^3)=x^2y^3     (You can't combine them because they have different variables of x and y)

x^3(x^5)=x^{(3+5)}=x^8

y^3(y^2)=y^{(3+2)}=y^5

There's two ways you can do this. Either by first making all the exponents positive then do subtraction, or multiply them then make all the exponents positive. I'm doing the 2nd way.

2w^7u^{-2}w^{-6}*9y^{-6}*2y^9u  You can combine the numbers 2 x 9 x 2 = 36

36w^7u^{-2}w^{-6}y^{-6}y^9u    Now multiply the terms with the same variables

36(w^{7+(-6)})(u^{(-2+1)})(y^{(-6+9)})    

36(w^1)(u^{-1})(y^3)     Now make all the exponents positive

\frac{36wy^3}{u}

If you were to do subtraction, here is what you need to know:

When you divide a variable with an exponent by a variable with an exponent, you subtract the exponents together. (Reminder: they have to be the same variable in order to combine the exponents)

For example:

\frac{x^3}{x^2} =x^{(3-2)}=x^1   or  x

\frac{y^2}{y^4} =y^{(2-4)}=y^{-2}=\frac{1}{y^2}

7 0
3 years ago
PLEASE HELP!
Citrus2011 [14]

Answer:

x - 3y - 7 = 0

Step-by-step explanation:

We can first write this equation in Point Slope form, and then rearrange it to general form.

Note: the given point is (h,k)

Slope is m.

The equation is:

y-k=m(x-h)

Therefore, the equation in point slope form would be:

y+2=1/3(x-1)

Now, we can change that to general form.

y+2=1/3x-1/3

1/3x-1/3-y-2=0

1/3x-y-2 1/3=0

Multiply everything by 3.

x-3y-7=0

Therefore, the corrrect answer is option 3.

5 0
3 years ago
Plz help my grade in math is a D and the quarter ends this week
igor_vitrenko [27]

Answer:

x=7

Step-by-step explanation:

if you look at this diagram as 2 triangles, the little one, and then the big one that the little one is inside of, and realize that they are similar triangles (by AAA standards) you can use a ration to solve the answer. the side length 9 is the length that is similar to side length 21, so you put those in a fraction format (9/21), and side length 3 is similar to side length x so you put those in a fraction (3/x), and then you create a ration with those

9/21=3/x

now you can cross-multiply 21 times three (63) and divide that number by 9 (7) to get your final answer of x=7.

Hope this helps!

5 0
3 years ago
(08.01) Two lines, A and B, are represented by the following equations: Line A: 3x + 3y = 12 Line B: x + y = 4 Which statement i
UkoKoshka [18]

Answer: There are infinitely many solutions.

Step-by-step explanation:

Given, Two lines, A and B, are represented by the following equations:

Line A: 3x + 3y = 12

Line B: x + y = 4

By comparing to the equations a_1x+b_1x=c_1 and a_2x+b_2x=c_2 respectively , we have

a_1=3,\ b_1=3\ \ \&\ c_1=12\\\\a_2=1,\ b_2=1\ \ \&\ c_2=4

Now , \dfrac{a_1}{a_2}=\dfrac{3}{1},\ \dfrac{b_1}{b_2}=\dfrac{3}{1},\ \&\ \dfrac{c_1}{c_2}=\dfrac{12}{4}=\dfrac{3}{1}

i.e. \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

It implies the gives lines are co-incident (linearly dependent).

That means it has infinitely many solutions.

So, the correct answer is "There are infinitely many solutions.".

6 0
3 years ago
Read 2 more answers
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