All categories

3 years ago

Write the equation of a line in POINT-SLOPE

Mathematics

1 answer:

Tems11 [23]3 years ago

4 0

Answer:

y - 2 = 1/2(x - 3)

Step-by-step explanation:

In this question, we need to write the given information in point-slope form.

Point-slope form: y - y1 = m(x - x1)

We know that our slope is 1/2

We are also given a coordinate: (3, 2)

Plug in the information to its correct spot in the equation:

y - 2 = 1/2(x - 3)

Your point-slope form would be: y - 2 = 1/2(x - 3)

You might be interested in

Can a local maximum also be a point of inflection? Explain.

myrzilka [38]

<span>Inflection points are where the function changes concavity. Since concave up corresponds to a positive second derivative and concave down corresponds to a negative second derivative, then when the function changes from concave up to concave down (or vise versa) the second derivative must equal zero at that point. So the second derivative must equal zero to be an inflection point. But don't get excited yet. You have to make sure that the concavity actually changes at that point.</span>

7 0

3 years ago

Hey help please math I need help good luck I’ll I’ve point

fredd [130]

Answer:

180 degrees

Step-by-step explanation:

180 degrees would flip the triangle halfway through a full circle. B is A upside down rotated halfway through a full circle.

7 0

2 years ago

Andrea has a goal of running at least 50 miles this month. She has already run 7 miles. How many miles does Andrea need to run e

Nuetrik [128]

Answer:

At least 1.72 miles per day.

Step-by-step explanation:

Given: Goal of running is at least 50 miles in a month.

Andrea have already run 7 miles.

Days left in the month is 25.

As given, Andrea have already run 7 miles.

∴ Andrea need to run this month= $50\ miles - 7\ miles= 43\ miles$

Days remaining this month is 25.

Now, finding miles need to run each day to meet her goal.

Miles need to run each day= $\frac{remaining\ miles}{remaining\ days}$

⇒ Miles need to run each day= $\frac{43}{25} = 1.72\ miles$

∴ Andrea need to run at least 1.72 miles to meet her goal this month.

8 0

3 years ago

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P'Q'R' has v

Serggg [28]

Step-by-step explanation:

that's for Part B

Part C: triangles PQR and P"Q"R" are not congruent since the corresponding sides are not equal

5 0

3 years ago

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{670 - 660}{9}$

$Z = 1.11$

$Z = 1.11$ has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0

2 years ago