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DerKrebs [107]
3 years ago
10

Write the equation of a line in POINT-SLOPE

Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

y - 2 = 1/2(x - 3)

Step-by-step explanation:

In this question, we need to write the given information in point-slope form.

Point-slope form: y - y1 = m(x - x1)

We know that our slope is 1/2

We are also given a coordinate: (3, 2)

Plug in the information to its correct spot in the equation:

y - 2 = 1/2(x - 3)

Your point-slope form would be: y - 2 = 1/2(x - 3)

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Answer:

"In three-dimensional geometry, skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron."

Step-by-step explanation:

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Can someone please answer. There is a picture. There is only one question. Thank you so much
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So than you check this graph so you see that the radius has a length of 4 units 
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3 years ago
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

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In the exam 45% students failed and 550 students were successful. The total number of students appeared in the exam.
TEA [102]

Answer:

1000

Step-by-step explanation:

7 0
3 years ago
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