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steposvetlana [31]
4 years ago
14

What is (6.2*10^4)*(3.3*10^2) in scientific notation

Mathematics
1 answer:
Free_Kalibri [48]4 years ago
8 0
<span>Its 2.046*10^7 hope this helps you :)</span>
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HELP PLEASE ASAP!!! CORRECT GETS BRAINLIEST!
ASHA 777 [7]

Answer:60

Step-by-step explanation:

5x4x3=60

6 0
3 years ago
if a, b, and c are prime numbers, do (a b) and c have a common factor that is greater than 1? (1) a, b, and c are all different
klio [65]

If a,b, and c are prime numbers, do (a*b) and c have a common factor that is greater than 1

(1) a,b, and c are all different prime numbers

(2) c≠2

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a b = 1*3 = 3

3 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a *b = 1*3 = 3

3 and 2 does not have a common factor aside 1

2. c \neq 2

Let's assume values of 2,7 and 3 to a b and c response

a * b = 2 *7 = 14

14 and 3 does not have a common factor aside 1

learn more about of prime number here

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8 0
1 year ago
Type the missing number in this sequence:
Gelneren [198K]
The answer would be 62
3 0
3 years ago
Read 2 more answers
: Use The TI Calculator To Answer The Question. Find The Probability That A Z-score Will Be Between 0.7 And 1.4. A) 0.242 O B) 0
ZanzabumX [31]

Answer:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case we want to find this probability:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

3 0
3 years ago
Read 2 more answers
You randomly guess the answers to two questions on a multiple-choice test. Each question has three choices: A, B, and C.
Fantom [35]

Answer: pick a bc its the first lettr of the alphebet

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3 years ago
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