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DedPeter [7]
3 years ago
13

Find the area enclosed by the graphs of y=√(4-4x), y=√(4-x) and x-axis by integrating with respect to x and integrating with res

pect to y g
Mathematics
1 answer:
Sloan [31]3 years ago
6 0

Answer:

(A) 2/3 [√(4-4x)]^3

(B) 2/3 [√(4-x)]^3

Step-by-step explanation:

Integrating the functions,

(A) Any function in square root is equal to or same as the function raised to the power of 1/2

To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2

Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.

Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.

Here, the denominator is 2, so you take the square root of the function, and raise the function to the power of 3

So the integral of Y = √[4-4x] is

2/3 [√(4-4x)]^3

(B) In like manner, the integral of

Y = √[4-x] is

2/3 [(√4-x)]^3

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a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

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Hence, the probability of between 5 and 12 is 0.7259

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3 years ago
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