Answer:
y = 3x - 16
Step-by-step explanation:
We are asked to find the equation of the line perpendicular to 2x + 6y = 30
We can use two formulas for this question, either
y = mx + c. Or
y - y_1 = m(x - x_1)
Step 1: calculate the slope
From the equation given
2x + 6y = 30
Make y the subject of the formula
6y = 30 - 2x
Or
6y = -2x + 30
Divide both sides by 6, to get y
6y/6 = ( -2x + 30)/6
y = (-2x + 30)/6
Separate them in order to get the slope
y = -2x/6 + 30/6
y = -1x/3 + 5
y = -x/3 + 5
Slope = -1/3
Step 2:
Note: if two lines are perpendicular to the other, both are negative reciprocal of each other
Perpendicular slope = 3/1
Substitute the slope into the equation
y = mx + c
y = 3x + c
Step 3: substitute the point into the equation
( 6,2)
x = 6
y = 2
2 = 3(6) + c
2 = 18 + c
Make the c the subject
2 - 18 =c
c = 2 - 18
c = -16
Step 4: sub the value of c into the equation
y = 3x + c
y = 3x - 16
The equation of the line is
y = 3x - 16
If you try out the other formula, u will get the same answer
