I need help I would really thank wheeler answers this for me

Mathematics

1 answer:

gavmur [86]3 years ago

3 0

It helps immensely if you know your times tables.

a) 36 = 6*6 = 2*3*2*3 = 2^2*3^2

b) 45 = 5*9 = 5*3*3 = 3^2*5

c) 2 is not a common factor; 3^2 is a common factor; 5 is not a common factor. The greatest common factor is 3^2 = 9.

d) The least common multiple can be found a couple of ways.

.. 1) the product of the distinct factors to their highest powers
.. .. .. 2^2 * 3^2 * 5 = 180

.. 2) the product of the numbers divided by their greatest common factor.
.. .. .. 36 * 45 / 9 = 180

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Water is pumped out of a holding tank at a rate of 6-6e^-0.13t liters/minute, where t is in minutes since the pump is started. I

astraxan [27]

Procedure:

1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and

2) Substract the result from the initial content of the tank (1000 liters).

Hands on:

Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =

= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =

6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters

2) 1000 liters - 313.865 liters = 613.135 liters

Answer: 613.135 liters

3 0

3 years ago

One point on the trend line is 200,6 using this point and the y-intercept find the slope of the trend line.

Marina CMI [18]

Step-by-step explanation:

Use the formula (Y2 - Y1)/(X2 - X1) to find the slope between two points

We'll make Point 1 (which is X1 and Y1) the Y-intercept so

X1, Y1 = (0, 5.00)

And we'll make Point 2 (which is X2 and Y2) the point on the trend line

X2, Y2 = (200, 6.00)

Plug into the formula:

(6.00 - 5.00)/(200 - 0)