All categories

3 years ago

What is the slope of the line represented by the equation y = 1/5x-3?

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

1/5

Step-by-step explanation:

Your equation is written in the form y=mx+b, where m is the slope and b is the y-intercept.

m=1/5, so the slope is 1/5

You might be interested in

Kelly made one batch of 1,425g of peanut and pretzel mix. How many grams does she need to add to the snack mix to make 2 kilogra

borishaifa [10]

Basically,

2 kg = 2,000 g

So all you need to do is

2,000
- 1,425
-----------
575

There's your answer!

575 grams

Hope that helps and correct me if I'm wrong!

5 0

3 years ago

Question 1<br> Let f(x) = 2x^2 - 3x - 4 and g(x) = x + 5. Find (fg)(x).

Scilla [17]

The function (fg)(x) is a composite function

The value of the function (fg)(x) is 2x^3 + 7x^2 - 19x - 20

<h3>How to determine the function (fg)(x)?</h3>

The functions are given as:

f(x) = 2x^2 - 3x - 4 and g(x) = x + 5.

To calculate (fg)(x), we make use of

(fg)(x) = f(x) * g(x)

So, we have:

(fg)(x) = (2x^2 - 3x - 4) * (x + 5)

Expand

(fg)(x) = 2x^3 - 3x^2 - 4x + 10x^2 - 15x - 20

Collect like terms

(fg)(x) = 2x^3 - 3x^2 + 10x^2 - 4x - 15x - 20

Evaluate

(fg)(x) = 2x^3 + 7x^2 - 19x - 20

Hence, the function (fg)(x) is 2x^3 + 7x^2 - 19x - 20

Read more about composite function at:

brainly.com/question/10687170

7 0

2 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago

Help With A Question

blondinia [14]

The anwser is 5.05 cm hahahahahahahahahahahahah

4 0

3 years ago

4/7 + 2/7 = ? can yall plzz help me simplify the awnser

noname [10]

Answer:

6/7 is the correct answr

4 0

3 years ago

Read 2 more answers