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3 years ago

A polynomial divided by a polynomial is a polynomial. always, sometimes, or never true?

Mathematics

1 answer:

Artemon [7]3 years ago

3 0

I think it is always true. I am not sure but I hope I'm right

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Jeremy will roll a number cube,numbered 1-6,twice.What is the probability of rolling an even number,then the number 3

gogolik [260]

I believe the answer is 1/12.

6 0

3 years ago

Time 6 years Interest rate 1.9% Principal- $850 What amount of simple interest will be earned? $16.15 O $96.90 $946.90 $9,690.00

Vaselesa [24]

Amount of simple interest will be earned is $96.90

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3 years ago

Sketch he graph of: <img src="https://tex.z-dn.net/?f=y%20%3D%202x%20-%204" id="TexFormula1" title="y = 2x - 4" alt="y = 2x -

Andreas93 [3]

Answer:

(Hope this helps can I pls have brainlist (crown) ☺️)

Step-by-step explanation:

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6 0

3 years ago

Solve for the value of x :- 5(x+4)+5(2-x)

Mariulka [41]

Answer:

$30$

Step-by-step explanation:

Given expression:

$5(x + 4) + 5(2 - x)$

Note: The value of "x" is undefined because the given sum is not an equation. Thus, I will simplify the expression as much as possible.

Let us simplify all the distributive properties stated in the expression.

Apply the distributive property rule [a(b + c) = ab + ac]

$\implies5(x) + 5(4) + 5(2) - 5(x)$

Since 5(x) is being subtracted from 5(x), we get:

$\implies 5(x) + 5(4) + 5(2) - 5(x)$

$\implies 5(4) + 5(2)$

Finally, let us simplify the sum of the product of (5 and 4) and (5 and 2).

$\implies20 + 10$

$\implies \boxed{30}$

Learn more about one-variable expressions: brainly.com/question/15139917

6 0

2 years ago

The commute times for workers in a city are normally distributed with an unknown population mean and standard deviation. If a ra

Elenna [48]

Answer:

The 95% confidence interval for population mean is (18.19, 23.81).

Step-by-step explanation:

The confidence interval for population mean using the Student's t-distribution is:

$CI=\bar x\pm t_{\alpha /2, (n-1)}\frac{s}{\sqrt{n} }$

Given:

$\bar x=21\\s=6\\n=20\\\alpha =1-0.95=0.05$

The critical value of t for α = 0.05 and degrees of freedom, (n - 1) = 19 is:

$t_{\alpha /2, (n-1)}=t_{0.05/2, 19}=2.093$

Compute the 95% confidence interval for population mean as follows:

$CI=\bar x\pm t_{\alpha /2, (n-1)}\frac{s}{\sqrt{n} }\\=21\pm2.093\times \frac{6}{\sqrt{20} }\\=21\pm2.81\\=(18.19, 23.81)$

Thus, the 95% confidence interval for population mean is (18.19, 23.81).

4 0

3 years ago