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Tomtit [17]
2 years ago
11

F(x) = 2 + 3x – 2x² Determine a, b and c

Mathematics
2 answers:
ololo11 [35]2 years ago
8 0

Answer:

a = -2

b =3

c =2

Step-by-step explanation:

f(x) = 2 + 3x – 2x²

Rewrite in descending powers of x

-2x^2 +3x+2

The form is ax^2 +bx +c

a = -2

b =3

c =2

RoseWind [281]2 years ago
3 0

Answer:

a = -2

b = 3

c = 2

Step-by-step explanation:

Put the equation in standard form:

f(x) = -2x² + 3x + 2

Now you can pull out the numbers for each variable.

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What is the slope of the line that contains the points (4, 3) and (2, 7)?​
zubka84 [21]

Answer:

-2

Step-by-step explanation:

given 2 points on a line (x1, yx) and (x2,y2)

the formula for slope, m  = (y2-y1) / (x2-x1)

in this case,

x1 = 4, y1 = 3, x2 = 2, y2 = 7

Hence,

m  = (7-3) / (2-4) = 4 / -2 = -2

8 0
3 years ago
= Homework: Special Right Triangles (8.2)
lubasha [3.4K]
rechecking this answer with your lecturer. Tq

4 0
2 years ago
Read 2 more answers
How would you do this question?
diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0
3 years ago
A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
  • A right square pyramid with base edges of length 8\sqrt{2}

Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

  • The height 3 units
  • A right square pyramid with base edges of length 4\sqrt{2}

So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
3 years ago
What is the height of the trapezoid if the Area = 26 un²?
Vladimir79 [104]

Answer:4

Step-by-step explanation:

H= 2*26/5+8

7 0
3 years ago
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