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Gnom [1K]
3 years ago
14

What is the solution to this system of equations? a+b=9 a-b=3

Mathematics
1 answer:
ladessa [460]3 years ago
8 0

Answer:

A. (6,3)

Step-by-step explanation:

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Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 blanket per d
Sauron [17]

Answer:

Since Darcie wants to crochet a minimum of 3 blankets and she crochets at a rate of 1/5 blanket per day, we can determine how many days she will need to crochet a minimum of 3 blankets following the next steps:

- Finding the number of days needed to crochet one (1) blanket:

\begin{gathered}1=\frac{1}{5}Crochet(Day)\\Crochet(Day)=5*1=5\end{gathered}

1=

5

1

Crochet(Day)

Crochet(Day)=5∗1=5

So, she can crochet 1 blanket every 5 days.

- Finding the number of days needed to crochet three (3) blankets:

If she needs 5 days to crochet 1 blanket, to crochet 3 blankets she will need 15 days because:

\begin{gathered}DaysNeeded=\frac{NumberOfBlankets}{Rate}\\\\DaysNeeded=\frac{3}{\frac{1}{5}}=3*5=15\end{gathered}

DaysNeeded=

Rate

NumberOfBlankets

DaysNeeded=

5

1

3

=3∗5=15

- Writing the inequality

If she has 60 days to crochet a minimum of 3 blankets but she can complete it in 15 days, she can skip crocheting 45 days because:

AvailableDays=60-RequiredDaysAvailableDays=60−RequiredDays

AvailableDays=60-15=45DaysAvailableDays=60−15=45Days

So, the inequality will be:

s\leq 45s≤45

The inequality means that she can skip crocheting a maximum of 45 days since she needs 15 days to crochet a minimum of 3 blankets.

Have a nice day!

3 0
3 years ago
The number of girls at middle school cyber summer camp was six more than twice the number of boys. There were a total of 156 mid
nordsb [41]
Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106
8 0
3 years ago
PLEASE HELP ME ASAP I WILL MARK YOU AS BRILLIANT<br>please help with these three
GalinKa [24]

Answer:

26:  x=34

28: x=17

30: m=30

Step-by-step explanation:

<u>26:</u> 2x+22=90

subtract 22

2x=68

divide by 2

x=34

<u>28:</u> 18+3x+21=90

add 18 and 21

3x+39=90

subtract 39

3x=51

divide by 3

x=17

<u>30:</u> 43+87+m+20=180

add 43 and 87 and 20

m+150=180

subtract 150

m=30

6 0
3 years ago
A dozen apples cost$4.92 for a dozen apples is a ratio of what per Apple
serg [7]

Answer:

12 : 4.92

Step-by-step explanation:

a= apples

12a=4.92

12 : 4.92

3 0
3 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
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