Answer:
1.6
Explanation:
1.598
Round from the nearest tenth
1.59
If the number in the hundredths place is higher then 5 then add one to the tenths place.
1.6
Answer:
<h2><u>
(0,0)</u></h2><h2><u>
(4,9)</u></h2><h2><u>
(-1,5)</u></h2><h2><u>
(-4,-8)</u></h2>
Step-by-step explanation:
When an inequality is graphed, the solutions will be shaded in a color. \
On this graph, it is shaded blue.
First we want to put all the points on the graph. During this step, it does not mater if the point is in the blue or not.
Now that we have all 8 points plotted, we can begin elimination.
For this step, we will cross out or eliminate any points in the white.
Any points in the blue, will be correct
After doing this step, you should have the answers <u>(0,0), (4,9), (-1,5), (-4,-8)</u>
So those are the correct answers
A lot trust me only like the first few chapters are only algebra 1 stuff other than that it’s mostly all new
Answer:
The greatest number of cycling outfits that Mr. Trager can buy would be 2.
Step-by-step explanation:
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.